5.4.6 Transformers
By the end of this lesson you can:
- Explain how a transformer works
- Use the turns ratio to calculate voltage and current
- Explain how transformers reduce power loss in transmission
Most of us encounter electrical transformers daily. The electronic device you are using right now connects to a mains supply delivering 120 V or 240 V AC, yet its internal microcircuits require a much lower voltage (such as 5 V or 12 V DC) to operate safely and efficiently. A transformer performs this critical task by stepping down or stepping up AC voltage levels.
The Physics of Mutual Induction
In essence, a transformer operates on the principles of Faraday's Law of Induction and conservation of energy through a process called mutual induction:
- Primary Circuit: An alternating current (AC) in the primary coil generates a continuously changing magnetic flux (ΔΦ⁄Δt).
- Iron Core: A soft iron core channels and concentrates this changing flux directly through to the secondary coil with minimal flux leakage.
- Secondary Circuit: As this changing magnetic flux cuts through the secondary coil, it induces an alternating electromotive force (EMF) across its terminals.
The Transformer Equations
The ratio of secondary voltage (Vs) to primary voltage (Vp) is strictly governed by the turns ratio of the two coils:
Assuming an ideal transformer (100% power efficiency where Pin = Pout, or VpIp = VsIs):
- Step-Up Transformer (Ns > Np): Increases voltage (Vs > Vp) while proportionally decreasing current (Is < Ip).
- Step-Down Transformer (Ns < Np): Decreases voltage (Vs < Vp) while proportionally increasing current (Is > Ip).
Watch the videos below to explore these mathematical models, examine how real-world transformers minimize energy losses (such as eddy current heating in laminated cores), and work through sample calculations.
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Check Your Understanding: Transformers
2. Power output: Pout = VsIs = 8.4 V × 1.2 A = 10.08 W.
3. Power lost: Plost = Pin − Pout = 27 W − 10.08 W = 16.92 W (an efficiency of about 37.3%).
1. Turns ratio: Np / Ns = Vp / Vs = 240 / 8.4 ≈ 28.6. A step-down transformer has more turns on the primary.
2. Power output: Pout = Vs × Is = 8.4 × 1.2 = 10.08 W.
3. Power lost: subtract the output from the input: 27 W − 10.08 W = 16.92 W. The 10.08 W is the power delivered, not the power lost.
Specialized Application: The Induction Coil
Standard transformers rely on an alternating current (AC) supply to generate a continuously changing magnetic flux. However, an induction coil (or Ruhmkorff coil) is a specialized electrical step-up transformer designed to generate extremely high-voltage electrical pulses from a low-voltage direct current (DC) power source, such as a battery.
How an Induction Coil Works
Because a steady DC source produces a constant magnetic field (ΔΦ⁄Δt = 0), an induction coil uses an automatic mechanical switch (an interrupter or contact breaker) to rapidly make and break the primary circuit:
- Rapid Flux Collapse: When the interrupter opens, the magnetic field in the soft iron core collapses almost instantaneously. This produces an extremely large rate of change of flux (ΔΦ⁄Δt) over a very short time interval (Δt).
- High Voltage Step-Up: According to Faraday's Law (ε = -N · ΔΦ⁄Δt), this rapid field collapse—combined with a secondary winding containing tens of thousands of turns (Ns >> Np)—induces high-voltage output pulses across the secondary terminals, often reaching tens of thousands of Volts.
- Role of the Capacitor: A capacitor connected across the interrupter contacts absorbs back-EMF energy to prevent sparking across the breaker points, causing an even sharper collapse of the primary magnetic field.
Watch the short video below to see a physical induction coil in action and examine how its interrupter mechanism produces high-voltage sparks.
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