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6.2.1 JJ Thomson and the Electron

By the end of this lesson you can:

  • Describe the cathode ray experiments
  • Explain how Thomson found the charge-to-mass ratio of the electron
  • Explain the significance of the discovery of the electron
🎥Watch
Learn the idea: a short explanation, then a check.

In this series of lessons, we explore a major paradigm shift in our understanding of matter and the fundamental nature of the atom.

We begin with J.J. Thomson’s discovery of the electron, progress to Ernest Rutherford’s revolutionary nuclear model, and conclude with James Chadwick’s discovery of the neutron—which appeared to complete the classical atomic model... or so they thought.

JJ Thomson

Following the development of the voltaic pile (battery) in the early 19th century, scientists began testing various materials to determine their electrical conductivity.

However, testing gases proved difficult until the invention of the Geissler tube in 1855, which made it possible to create a sealed glass tube containing gas at low pressure. In 1859, Julius Plücker successfully sealed electrode wires directly into these vacuum tubes, allowing electric current to pass through the partial vacuum.

Physicists observed that at specific low pressures, a glowing beam appeared inside the tube. This sparked a central debate: was this ray a form of electromagnetic radiation, as James Clerk Maxwell’s theories suggested, or was it a stream of moving charged particles?

Prior to 1897, the atom was considered the fundamental, indivisible unit of matter—in fact, the word atom comes from the Greek atomos, meaning "uncuttable." However, in 1897, J.J. Thomson conducted a landmark series of experiments using crossed electric and magnetic fields. He discovered that cathode rays were composed of previously unknown subatomic particles, which we now know as electrons. Thomson’s discovery revolutionized our understanding of atomic structure and paved the way for modern quantum mechanics

Theory
​Watch the video to find out why 
(you may need to review charge behaviour in electric fields and charge behaviour in magnetic fields)
🕹️Explore
Test your predictions in a simulation.

Learn more about JJ Thomson's set up. Follow the instructions

📝Practise
Worked examples first, then problems to try, then worksheets.
Problems to try

Practice Problems: Crossed Electric and Magnetic Fields

When a charged particle passes through crossed electric and magnetic fields without being deflected, the electric and magnetic forces on it are equal and opposite, so qE = qvB and v = E / B. Electric field intensity can be written in N C-1 or V/m.

1. A beam of electrons travels undeflected through a set of crossed electric and magnetic fields. What is the speed of the electrons if the magnetic field is 82 mT and the electric field is 5.8 × 104 N C-1?

Given: B = 82 mT = 8.2 × 10-2 T, E = 5.8 × 104 N C-1

Condition: The electrons are undeflected, so the electric force balances the magnetic force: qE = qvB

Formula: v = E / B

Calculation: v = (5.8 × 104) / (8.2 × 10-2) = 7.07 × 105 m s-1

Answer: 7.07 × 105 m s-1
2. Electrons moving at 7.5 × 106 m s-1 pass through crossed magnetic and electric fields undeflected. What is the magnitude of the magnetic field if the electric field is 4.4 × 104 N C-1?

Given: v = 7.5 × 106 m s-1, E = 4.4 × 104 N C-1

Condition: The electrons are undeflected, so qE = qvB

Formula: B = E / v

Calculation: B = (4.4 × 104) / (7.5 × 106) = 5.87 × 10-3 T

Answer: 5.87 × 10-3 T (5.87 mT)
3. Electrons enter a region of crossed fields with a speed of 2.0 × 106 m s-1. The electric field is 3.0 × 103 N C-1 and the magnetic field is 2.0 mT. (a) What speed of electron would pass through undeflected? (b) Are these electrons deflected? If so, is the electric force or the magnetic force on them larger?

Given: v = 2.0 × 106 m s-1, E = 3.0 × 103 N C-1, B = 2.0 mT = 2.0 × 10-3 T, q = 1.60 × 10-19 C

(a) Undeflected speed: v = E / B = (3.0 × 103) / (2.0 × 10-3) = 1.5 × 106 m s-1

(b) Compare the forces:

Electric force: FE = qE = 1.60 × 10-19 × 3.0 × 103 = 4.8 × 10-16 N

Magnetic force: FB = qvB = 1.60 × 10-19 × 2.0 × 106 × 2.0 × 10-3 = 6.4 × 10-16 N

The electrons are faster than 1.5 × 106 m s-1, so the magnetic force is the larger one and the beam is deflected in the direction of the magnetic force. (Electrons slower than 1.5 × 106 m s-1 would be deflected the other way, in the direction of the electric force.)

Answer: (a) 1.5 × 106 m s-1, (b) Yes. The magnetic force (6.4 × 10-16 N) is larger than the electric force (4.8 × 10-16 N).
This demonstration of an aspect of the JJ Thomson experiment is done in conjunction with University of Sydney Kickstart program and Crooked Science