Binding Energy

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A quick summary on Binding energy, useful for review
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Imagine a lego kit. You weigh the parts and get a certain mass.
You complete the project and when you weigh the final project, its less than what you started with.


But you haven't lost a piece!


In fact, when you pull the whole project apart , all the parts have the same mass you initially measured.

This analogy describe the nucleus and the idea of mass defect and binding energy.

Before we explain binding energy lets first look at mass defect.
Image description
Mass Defect
When nucleus transmutes, such as in the case of alpha or beta decay, energy is released. But where does that energy come from? (It also occurs in nuclear fission and fusion, which we will discuss shortly)
The answer simply is from the matter itself.
Like a chemical reaction where you have reactants and products, so too,  in nuclear reactions you have a reactant or reactants which results in the production of the products.


During the process of the nuclear reaction there is less mass in the products than the reactants.
This seems to violate one of the conservation laws:  one of the conservation of matter. But the fact is the mass lost is converted into energy - the mass defect.
Some more correctly the conservation laws is about the conservation of mass-energy, mass is just the concentration of energy by way  of E=mc^2
This is referred to as the mass defect. 
And it is that mass difference that converts to energy by way of Einstein's famous equation.
But in nuclear physics, is is more helpful to to use a non SI unit for mass, as well as for energy
So instead of using the joule (J) for energy we can use the electron volt (eV)
And for mass , instead if using the kilogram, we use the atomic mass unit (u).
The video covers this 
​Before you continue however, make sure you are familiar with the electron volt (eV) as a unit of energy - If not, please review here.

Now that we understand mass defect, let's explore the concept of binding energy.

Consider constructing a chlorine atom from scratch: it consists of 17 protons, 17 electrons, and 18 neutrons. However, if you sum the individual masses of these constituent particles, the total is greater than the actual mass of a combined chlorine atom. There is still a mass defect!

Watch the video below to see how mass defect connects directly to nuclear binding energy.

(Note: The video includes a brief review of the atomic mass unit. If you want to jump straight to binding energy, skip ahead to 3:25.)

Sample Problem
We are now ready to try a sample problem
Below is a sample problem with a video that explain how to solve it. It is suggested you try the problem beforehand, as this actually aids understanding, even if you are unsure if you are correct.
Picture

Practice Problems: Mass Defect & Binding Energy

Useful Constants:
• Mass of proton (mp) = 1.007276 u
• Mass of neutron (mn) = 1.008665 u
• 1 u = 931.5 MeV/c2 (931.5 MeV per mass unit)

1. Calculate the mass defect (Δm) of a Helium-4 nucleus (42He), given its measured nuclear mass is 4.001506 u.

Answer: Δm = 0.030376 u

Solution:
1. A Helium-4 nucleus contains 2 protons and 2 neutrons.
2. Total mass of individual nucleons = (2 × 1.007276 u) + (2 × 1.008665 u) = 4.031882 u.
3. Subtract actual nuclear mass: Δm = 4.031882 u − 4.001506 u = 0.030376 u.

2. Determine the total nuclear binding energy (Eb) of the Helium-4 nucleus in Mega-electronvolts (MeV).

Answer: Eb = 28.295 MeV

Solution:
Multiply the mass defect (Δm = 0.030376 u) by the energy conversion factor (931.5 MeV/u):
Eb = 0.030376 u × 931.5 MeV/u = 28.295 MeV.

3. What is the binding energy per nucleon (Eb / A) for Helium-4?

Answer: 7.074 MeV / nucleon

Solution:
Helium-4 has a total of A = 4 nucleons (2 protons + 2 neutrons).
Divide total binding energy by nucleon count: 28.295 MeV ÷ 4 = 7.074 MeV / nucleon.

4. An Iron-56 nucleus (5626Fe) has a mass defect of 0.52846 u. Calculate its binding energy per nucleon.

Answer: 8.79 MeV / nucleon

Solution:
1. Total Binding Energy = 0.52846 u × 931.5 MeV/u = 492.26 MeV.
2. Divide by total nucleons (A = 56): 492.26 MeV ÷ 56 = 8.79 MeV / nucleon.

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