Transformers

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Most of us encounter electrical transformers daily. The electronic device you are using right now connects to a mains supply delivering 120 V or 240 V AC, yet its internal microcircuits require a much lower voltage (such as 5 V or 12 V DC) to operate safely and efficiently. A transformer performs this critical task by stepping down or stepping up AC voltage levels.

The Physics of Mutual Induction

In essence, a transformer operates on the principles of Faraday's Law of Induction and conservation of energy through a process called mutual induction:

  • Primary Circuit: An alternating current (AC) in the primary coil generates a continuously changing magnetic flux (ΔΦ⁄Δt).
  • Iron Core: A soft iron core channels and concentrates this changing flux directly through to the secondary coil with minimal flux leakage.
  • Secondary Circuit: As this changing magnetic flux cuts through the secondary coil, it induces an alternating electromotive force (EMF) across its terminals.

The Transformer Equations

The ratio of secondary voltage (Vs) to primary voltage (Vp) is strictly governed by the turns ratio of the two coils:

VpVs = NpNs = IsIp

Assuming an ideal transformer (100% power efficiency where Pin = Pout, or VpIp = VsIs):

  • Step-Up Transformer (Ns > Np): Increases voltage (Vs > Vp) while proportionally decreasing current (Is < Ip).
  • Step-Down Transformer (Ns < Np): Decreases voltage (Vs < Vp) while proportionally increasing current (Is > Ip).

Watch the videos below to explore these mathematical models, examine how real-world transformers minimize energy losses (such as eddy current heating in laminated cores), and work through sample calculations.

 Check your understanding.

Check Your Understanding: Transformer Calculations & Efficiency

Question: A battery charger (step-down transformer) is connected to a 240 V AC supply and has a primary power input rating of 27 W. It charges a battery by delivering 8.4 V at a maximum current of 1.2 A. What is the turns ratio (Np / Ns) and how much power is lost as heat during operation?

Sample problem
Picture

Specialized Application: The Induction Coil

Standard transformers rely on an alternating current (AC) supply to generate a continuously changing magnetic flux. However, an induction coil (or Ruhmkorff coil) is a specialized electrical step-up transformer designed to generate extremely high-voltage electrical pulses from a low-voltage direct current (DC) power source, such as a battery.

How an Induction Coil Works

Because a steady DC source produces a constant magnetic field (ΔΦ⁄Δt = 0), an induction coil uses an automatic mechanical switch (an interrupter or contact breaker) to rapidly make and break the primary circuit:

  • Rapid Flux Collapse: When the interrupter opens, the magnetic field in the soft iron core collapses almost instantaneously. This produces an extremely large rate of change of flux (ΔΦΔt) over a very short time interval (Δt).
  • High Voltage Step-Up: According to Faraday's Law (ε = -N · ΔΦΔt), this rapid field collapse—combined with a secondary winding containing tens of thousands of turns (Ns >> Np)—induces high-voltage output pulses across the secondary terminals, often reaching tens of thousands of Volts.
  • Role of the Capacitor: A capacitor connected across the interrupter contacts absorbs back-EMF energy to prevent sparking across the breaker points, causing an even sharper collapse of the primary magnetic field.

Watch the short video below to see a physical induction coil in action and examine how its interrupter mechanism produces high-voltage sparks.

 

How well do you know the transformers?


​Test your understanding of transformers. So do the quiz and try to get full marks

Then check your understanding if necessary with the video
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